14(y-5)+3=12(3y+2)

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Solution for 14(y-5)+3=12(3y+2) equation:



14(y-5)+3=12(3y+2)
We move all terms to the left:
14(y-5)+3-(12(3y+2))=0
We multiply parentheses
14y-(12(3y+2))-70+3=0
We calculate terms in parentheses: -(12(3y+2)), so:
12(3y+2)
We multiply parentheses
36y+24
Back to the equation:
-(36y+24)
We add all the numbers together, and all the variables
14y-(36y+24)-67=0
We get rid of parentheses
14y-36y-24-67=0
We add all the numbers together, and all the variables
-22y-91=0
We move all terms containing y to the left, all other terms to the right
-22y=91
y=91/-22
y=-4+3/22

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