14(z+2)-3(z-2)=5(z-1)+5(z-2)

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Solution for 14(z+2)-3(z-2)=5(z-1)+5(z-2) equation:


14(z+2)-3(z-2)=5(z-1)+5(z-2)

We simplify the equation to the form, which is simple to understand 
14(z+2)-3(z-2)=5(z-1)+5(z-2)

Reorder the terms in parentheses
+(+14z+28)-3*(z-2)=5*(z-1)+5*(z-2)

Remove unnecessary parentheses
+14z+28-3+*(+z-2+)=+5+*(+z-1+)+5+*(+z-2+)

Reorder the terms in parentheses
+14z+28+(-3z+6)=5*(z-1)+5*(z-2)

Remove unnecessary parentheses
+14z+28-3z+6=+5+*(+z-1+)+5+*(+z-2+)

Reorder the terms in parentheses
+14z+28-3z+6=+(+5z-5)+5*(z-2)

Remove unnecessary parentheses
+14z+28-3z+6=+5z-5+5+*(+z-2+)

Reorder the terms in parentheses
+14z+28-3z+6=+5z-5+(+5z-10)

Remove unnecessary parentheses
+14z+28-3z+6=+5z-5+5z-10

We move all terms containing z to the left and all other terms to the right. 
+14z-3z-5z-5z=-5-10-28-6

We simplify left and right side of the equation. 
+1z=-49

We divide both sides of the equation by 1 to get z. 
z=-49

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