14(z+3)=14z+2114(z+3)=14z+2114,

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Solution for 14(z+3)=14z+2114(z+3)=14z+2114, equation: 



14(z+3)=14z+2114(z+3)=14z+2114.

We move all terms to the left:

14(z+3)-(14z+2114(z+3))=0

We multiply parentheses

14z-(14z+2114(z+3))+42=0



We calculate terms in parentheses: -(14z+2114(z+3)), so:

14z+2114(z+3)

We multiply parentheses

14z+2114z+6342

We add all the numbers together, and all the variables

2128z+6342

Back to the equation:

-(2128z+6342)



We get rid of parentheses

14z-2128z-6342+42=0

We add all the numbers together, and all the variables

-2114z-6300=0

We move all terms containing z to the left, all other terms to the right

-2114z=6300

z=6300/-2114

z=-2+148/151

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