14+(-3)(5t+(-12))=1+(-1)(20t+1)

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Solution for 14+(-3)(5t+(-12))=1+(-1)(20t+1) equation: 



14+(-3)(5t+(-12))=1+(-1)(20t+1)

We move all terms to the left:

14+(-3)(5t+(-12))-(1+(-1)(20t+1))=0

We multiply parentheses ..

(-3)(5t+(-12))-(1+(-20t-1))+14=0



We calculate terms in parentheses: +(-3)(5t+(-12)), so:

-3)(5t+(-12)

We add all the numbers together, and all the variables

-3)(5t-12

Back to the equation:

+(-3)(5t-12)





We calculate terms in parentheses: -(1+(-20t-1)), so:

1+(-20t-1)

determiningTheFunctionDomain
(-20t-1)+1

We get rid of parentheses

-20t-1+1

We add all the numbers together, and all the variables

-20t

Back to the equation:

-(-20t)



We get rid of parentheses

(-3)(5t-12)+20t+14=0

We multiply parentheses ..

(-15t+36)+20t+14=0

We add all the numbers together, and all the variables

20t+(-15t+36)+14=0

We get rid of parentheses

20t-15t+36+14=0

We add all the numbers together, and all the variables

5t+50=0

We move all terms containing t to the left, all other terms to the right

5t=-50

t=-50/5

t=-10

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