14+-1(x+-5)=3(x+9)+-10

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Solution for 14+-1(x+-5)=3(x+9)+-10 equation: 



14+-1(x+-5)=3(x+9)+-10

We move all terms to the left:

14+-1(x+-5)-(3(x+9)+-10)=0

We add all the numbers together, and all the variables

-1(x-5)-(3(x+9)+-10)+14+=0

We add all the numbers together, and all the variables

-1(x-5)-(3(x+9)+-10)=0

We use the square of the difference formula

-1(x-5)-(3(x+9)-10)=0



We calculate terms in parentheses: -(3(x+9)-10), so:

3(x+9)-10

We multiply parentheses

3x+27-10

We add all the numbers together, and all the variables

3x+17

Back to the equation:

-(3x+17)



We get rid of parentheses

-1(x-5)-3x-17=0

We add all the numbers together, and all the variables

-3x-1(x-5)-17=0

We move all terms containing x to the left, all other terms to the right

-3x-1(x-5)=17

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