14+1/4x-20=1/2x-4

Solution for 14+1/4x-20=1/2x-4 equation:

14+1/4x-20=1/2x-4

We move all terms to the left:

14+1/4x-20-(1/2x-4)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 2x-4)!=0

x∈R


We add all the numbers together, and all the variables

1/4x-(1/2x-4)-6=0

We get rid of parentheses

1/4x-1/2x+4-6=0

We calculate fractions


2x/8x^2+(-4x)/8x^2+4-6=0

We add all the numbers together, and all the variables

2x/8x^2+(-4x)/8x^2-2=0

We multiply all the terms by the denominator


2x+(-4x)-2*8x^2=0

Wy multiply elements

-16x^2+2x+(-4x)=0

We get rid of parentheses

-16x^2+2x-4x=0

We add all the numbers together, and all the variables

-16x^2-2x=0

a = -16; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-16)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-16}=\frac{0}{-32}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-16}=\frac{4}{-32}
=-1/8
$