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14+2x=15+3/2x
We move all terms to the left:
14+2x-(15+3/2x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2x-(3/2x+15)+14=0
We get rid of parentheses
2x-3/2x-15+14=0
We multiply all the terms by the denominator
2x*2x-15*2x+14*2x-3=0
Wy multiply elements
4x^2-30x+28x-3=0
We add all the numbers together, and all the variables
4x^2-2x-3=0
a = 4; b = -2; c = -3;
Δ = b2-4ac
Δ = -22-4·4·(-3)
Δ = 52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{52}=\sqrt{4*13}=\sqrt{4}*\sqrt{13}=2\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{13}}{2*4}=\frac{2-2\sqrt{13}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{13}}{2*4}=\frac{2+2\sqrt{13}}{8} $
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