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14+2x=16+(3/2)x
We move all terms to the left:
14+2x-(16+(3/2)x)=0
Domain of the equation: 2)x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2x-(16+(+3/2)x)+14=0
We multiply all the terms by the denominator
2x*2)x)-(16+(+14*2)x)+3=0
We add all the numbers together, and all the variables
2x*2)x)-(16+28x)+3=0
Wy multiply elements
4x^2=0
a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{8}=0$
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