14+3(5t-12)=1-(20t+1)

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Solution for 14+3(5t-12)=1-(20t+1) equation: 



14+3(5t-12)=1-(20t+1)

We move all terms to the left:

14+3(5t-12)-(1-(20t+1))=0

We multiply parentheses

15t-(1-(20t+1))-36+14=0



We calculate terms in parentheses: -(1-(20t+1)), so:

1-(20t+1)

determiningTheFunctionDomain
-(20t+1)+1

We get rid of parentheses

-20t-1+1

We add all the numbers together, and all the variables

-20t

Back to the equation:

-(-20t)



We add all the numbers together, and all the variables

15t-(-20t)-22=0

We get rid of parentheses

15t+20t-22=0

We add all the numbers together, and all the variables

35t-22=0

We move all terms containing t to the left, all other terms to the right

35t=22

t=22/35

t=22/35

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