14+3c=-3(c-4)+8c

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Solution for 14+3c=-3(c-4)+8c equation:



14+3c=-3(c-4)+8c
We move all terms to the left:
14+3c-(-3(c-4)+8c)=0
We calculate terms in parentheses: -(-3(c-4)+8c), so:
-3(c-4)+8c
We add all the numbers together, and all the variables
8c-3(c-4)
We multiply parentheses
8c-3c+12
We add all the numbers together, and all the variables
5c+12
Back to the equation:
-(5c+12)
We get rid of parentheses
3c-5c-12+14=0
We add all the numbers together, and all the variables
-2c+2=0
We move all terms containing c to the left, all other terms to the right
-2c=-2
c=-2/-2
c=1

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