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14+3x=49/x
We move all terms to the left:
14+3x-(49/x)=0
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3x-(+49/x)+14=0
We get rid of parentheses
3x-49/x+14=0
We multiply all the terms by the denominator
3x*x+14*x-49=0
We add all the numbers together, and all the variables
14x+3x*x-49=0
Wy multiply elements
3x^2+14x-49=0
a = 3; b = 14; c = -49;
Δ = b2-4ac
Δ = 142-4·3·(-49)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-28}{2*3}=\frac{-42}{6} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+28}{2*3}=\frac{14}{6} =2+1/3 $
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