14+x=(3/10)x

Solution for 14+x=(3/10)x equation:

14+x=(3/10)x

We move all terms to the left:

14+x-((3/10)x)=0


Domain of the equation: 10)x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x-((+3/10)x)+14=0

We multiply all the terms by the denominator


x*10)x)-((+14*10)x)+3=0

We add all the numbers together, and all the variables

x*10)x)-(140x)+3=0

We add all the numbers together, and all the variables

x*10)x)-140x+3=0

Wy multiply elements

10x^2=0

a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{20}=0$