14-(1/5)(j-10)=(2/5)(25+j)

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Solution for 14-(1/5)(j-10)=(2/5)(25+j) equation: 


j in (-oo:+oo)

14-((1/5)*(j-10)) = (2/5)*(j+25) // - (2/5)*(j+25)

14-((1/5)*(j-10))-((2/5)*(j+25)) = 0

(-1/5)*(j-10)+(-2/5)*(j+25)+14 = 0

14-1/5*(j-10)-2/5*(j+25) = 0

14-1/5*(j-10)-2/5*(j+25) = 0

14-3/5*j-8 = 0

6-3/5*j = 0

6-3/5*j = 0

6-3/5*j = 0 // - 6

-3/5*j = -6 // : -3/5

j = -6/(-3/5)

j = 10

j = 10

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