14-(12-4y)=1/2(8y+3)

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Solution for 14-(12-4y)=1/2(8y+3) equation: 



14-(12-4y)=1/2(8y+3)

We move all terms to the left:

14-(12-4y)-(1/2(8y+3))=0



Domain of the equation: 2(8y+3))!=0

y∈R



We add all the numbers together, and all the variables

-(-4y+12)-(1/2(8y+3))+14=0

We get rid of parentheses

4y-(1/2(8y+3))-12+14=0

We multiply all the terms by the denominator


4y*2(8y+3))-(1-12*2(8y+3))+14*2(8y+3))=0

We add all the numbers together, and all the variables

4y*2(8y+3))-(1-12*2(8y+3))+14*2(8y=0

Wy multiply elements

8y^2(8-48y^2(8=0

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