14-(2x-5)-(2x+1)=2+7x+3+3(x+2)

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Solution for 14-(2x-5)-(2x+1)=2+7x+3+3(x+2) equation: 



14-(2x-5)-(2x+1)=2+7x+3+3(x+2)

We move all terms to the left:

14-(2x-5)-(2x+1)-(2+7x+3+3(x+2))=0

We get rid of parentheses

-2x-2x-(2+7x+3+3(x+2))+5-1+14=0



We calculate terms in parentheses: -(2+7x+3+3(x+2)), so:

2+7x+3+3(x+2)

determiningTheFunctionDomain
7x+3(x+2)+2+3

We add all the numbers together, and all the variables

7x+3(x+2)+5

We multiply parentheses

7x+3x+6+5

We add all the numbers together, and all the variables

10x+11

Back to the equation:

-(10x+11)



We add all the numbers together, and all the variables

-4x-(10x+11)+18=0

We get rid of parentheses

-4x-10x-11+18=0

We add all the numbers together, and all the variables

-14x+7=0

We move all terms containing x to the left, all other terms to the right

-14x=-7

x=-7/-14

x=1/2

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