14-(5-3x)=4(-9+x)+48

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Solution for 14-(5-3x)=4(-9+x)+48 equation: 



14-(5-3x)=4(-9+x)+48

We move all terms to the left:

14-(5-3x)-(4(-9+x)+48)=0

We add all the numbers together, and all the variables

-(-3x+5)-(4(x-9)+48)+14=0

We get rid of parentheses

3x-(4(x-9)+48)-5+14=0



We calculate terms in parentheses: -(4(x-9)+48), so:

4(x-9)+48

We multiply parentheses

4x-36+48

We add all the numbers together, and all the variables

4x+12

Back to the equation:

-(4x+12)



We add all the numbers together, and all the variables

3x-(4x+12)+9=0

We get rid of parentheses

3x-4x-12+9=0

We add all the numbers together, and all the variables

-1x-3=0

We move all terms containing x to the left, all other terms to the right

-x=3

x=3/-1

x=-3

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