14-(6x-18)2x=26-12x-3x+6+11x

Solution for 14-(6x-18)2x=26-12x-3x+6+11x equation:

14-(6x-18)2x=26-12x-3x+6+11x

We move all terms to the left:

14-(6x-18)2x-(26-12x-3x+6+11x)=0

We add all the numbers together, and all the variables

-(6x-18)2x-(-4x+32)+14=0

We multiply parentheses

-12x^2+36x-(-4x+32)+14=0

We get rid of parentheses

-12x^2+36x+4x-32+14=0

We add all the numbers together, and all the variables

-12x^2+40x-18=0

a = -12; b = 40; c = -18;
Δ = b2-4ac
Δ = 402-4·(-12)·(-18)
Δ = 736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{736}=\sqrt{16*46}=\sqrt{16}*\sqrt{46}=4\sqrt{46}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-4\sqrt{46}}{2*-12}=\frac{-40-4\sqrt{46}}{-24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+4\sqrt{46}}{2*-12}=\frac{-40+4\sqrt{46}}{-24}
$