14-(8x-4)+6x=4(3x+2)

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Solution for 14-(8x-4)+6x=4(3x+2) equation: 



14-(8x-4)+6x=4(3x+2)

We move all terms to the left:

14-(8x-4)+6x-(4(3x+2))=0

We add all the numbers together, and all the variables

6x-(8x-4)-(4(3x+2))+14=0

We get rid of parentheses

6x-8x-(4(3x+2))+4+14=0



We calculate terms in parentheses: -(4(3x+2)), so:

4(3x+2)

We multiply parentheses

12x+8

Back to the equation:

-(12x+8)



We add all the numbers together, and all the variables

-2x-(12x+8)+18=0

We get rid of parentheses

-2x-12x-8+18=0

We add all the numbers together, and all the variables

-14x+10=0

We move all terms containing x to the left, all other terms to the right

-14x=-10

x=-10/-14

x=5/7

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