14-(x-4)=3(x+2)

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Solution for 14-(x-4)=3(x+2) equation:



14-(x-4)=3(x+2)
We move all terms to the left:
14-(x-4)-(3(x+2))=0
We get rid of parentheses
-x-(3(x+2))+4+14=0
We calculate terms in parentheses: -(3(x+2)), so:
3(x+2)
We multiply parentheses
3x+6
Back to the equation:
-(3x+6)
We add all the numbers together, and all the variables
-1x-(3x+6)+18=0
We get rid of parentheses
-1x-3x-6+18=0
We add all the numbers together, and all the variables
-4x+12=0
We move all terms containing x to the left, all other terms to the right
-4x=-12
x=-12/-4
x=+3

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