14-(x-4)=3(x+2)

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Solution for 14-(x-4)=3(x+2) equation: 



14-(x-4)=3(x+2)

We move all terms to the left:

14-(x-4)-(3(x+2))=0

We get rid of parentheses

-x-(3(x+2))+4+14=0



We calculate terms in parentheses: -(3(x+2)), so:

3(x+2)

We multiply parentheses

3x+6

Back to the equation:

-(3x+6)



We add all the numbers together, and all the variables

-1x-(3x+6)+18=0

We get rid of parentheses

-1x-3x-6+18=0

We add all the numbers together, and all the variables

-4x+12=0

We move all terms containing x to the left, all other terms to the right

-4x=-12

x=-12/-4

x=+3

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