14-(x/3+x)=2

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Solution for 14-(x/3+x)=2 equation: 



14-(x/3+x)=2

We move all terms to the left:

14-(x/3+x)-(2)=0



Domain of the equation: 3+x)!=0

We move all terms containing x to the left, all other terms to the right

x)!=-3

x!=-3/1

x!=-3

x∈R



We add all the numbers together, and all the variables

-(+x+x/3)+14-2=0

We add all the numbers together, and all the variables

-(+x+x/3)+12=0

We get rid of parentheses

-x-x/3+12=0

We multiply all the terms by the denominator


-x*3-x+12*3=0

We add all the numbers together, and all the variables

-1x-x*3+36=0

Wy multiply elements

-1x-3x+36=0

We add all the numbers together, and all the variables

-4x+36=0

We move all terms containing x to the left, all other terms to the right

-4x=-36

x=-36/-4

x=+9

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