14-1/5(j-10)2/5(25+t)

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Solution for 14-1/5(j-10)2/5(25+t) equation: 


x in (-oo:+oo)

14-((((1/5)*(j-10)^2)/5)*(t+25)) = 0

(-1/25)*(j-10)^2*(t+25)+14 = 0

14-1/25*(j-10)^2*(t+25) = 0

14-1/25*(j-10)^2*(t+25) = 0

20*j-j^2-1/25*j^2*t+4/5*j*t-4*t-86 = 0

20*j-j^2-1/25*j^2*t+4/5*j*t-4*t-86 = 0

x belongs to the empty set

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