14-2(3m+1)=6(4+m)

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Solution for 14-2(3m+1)=6(4+m) equation: 



14-2(3m+1)=6(4+m)

We move all terms to the left:

14-2(3m+1)-(6(4+m))=0

We add all the numbers together, and all the variables

-2(3m+1)-(6(m+4))+14=0

We multiply parentheses

-6m-(6(m+4))-2+14=0



We calculate terms in parentheses: -(6(m+4)), so:

6(m+4)

We multiply parentheses

6m+24

Back to the equation:

-(6m+24)



We add all the numbers together, and all the variables

-6m-(6m+24)+12=0

We get rid of parentheses

-6m-6m-24+12=0

We add all the numbers together, and all the variables

-12m-12=0

We move all terms containing m to the left, all other terms to the right

-12m=12

m=12/-12

m=-1

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