14-2(3p+1)=6(p+1)

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Solution for 14-2(3p+1)=6(p+1) equation: 



14-2(3p+1)=6(p+1)

We move all terms to the left:

14-2(3p+1)-(6(p+1))=0

We multiply parentheses

-6p-(6(p+1))-2+14=0



We calculate terms in parentheses: -(6(p+1)), so:

6(p+1)

We multiply parentheses

6p+6

Back to the equation:

-(6p+6)



We add all the numbers together, and all the variables

-6p-(6p+6)+12=0

We get rid of parentheses

-6p-6p-6+12=0

We add all the numbers together, and all the variables

-12p+6=0

We move all terms containing p to the left, all other terms to the right

-12p=-6

p=-6/-12

p=1/2

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