14-2(3p+1)=6(p+4)

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Solution for 14-2(3p+1)=6(p+4) equation: 



14-2(3p+1)=6(p+4)

We move all terms to the left:

14-2(3p+1)-(6(p+4))=0

We multiply parentheses

-6p-(6(p+4))-2+14=0



We calculate terms in parentheses: -(6(p+4)), so:

6(p+4)

We multiply parentheses

6p+24

Back to the equation:

-(6p+24)



We add all the numbers together, and all the variables

-6p-(6p+24)+12=0

We get rid of parentheses

-6p-6p-24+12=0

We add all the numbers together, and all the variables

-12p-12=0

We move all terms containing p to the left, all other terms to the right

-12p=12

p=12/-12

p=-1

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