14-2(3p+1)=6+(4+p)

Solution for 14-2(3p+1)=6+(4+p) equation:

14-2(3p+1)=6+(4+p)

We move all terms to the left:

14-2(3p+1)-(6+(4+p))=0

We add all the numbers together, and all the variables

-2(3p+1)-(6+(p+4))+14=0

We multiply parentheses

-6p-(6+(p+4))-2+14=0


We calculate terms in parentheses: -(6+(p+4)), so:

6+(p+4)

determiningTheFunctionDomain
(p+4)+6

We get rid of parentheses

p+4+6

We add all the numbers together, and all the variables

p+10

Back to the equation:

-(p+10)


We add all the numbers together, and all the variables

-6p-(p+10)+12=0

We get rid of parentheses

-6p-p-10+12=0

We add all the numbers together, and all the variables

-7p+2=0

We move all terms containing p to the left, all other terms to the right

-7p=-2

p=-2/-7

p=2/7