14-2(3r+1)=6(4+r)

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Solution for 14-2(3r+1)=6(4+r) equation:



14-2(3r+1)=6(4+r)
We move all terms to the left:
14-2(3r+1)-(6(4+r))=0
We add all the numbers together, and all the variables
-2(3r+1)-(6(r+4))+14=0
We multiply parentheses
-6r-(6(r+4))-2+14=0
We calculate terms in parentheses: -(6(r+4)), so:
6(r+4)
We multiply parentheses
6r+24
Back to the equation:
-(6r+24)
We add all the numbers together, and all the variables
-6r-(6r+24)+12=0
We get rid of parentheses
-6r-6r-24+12=0
We add all the numbers together, and all the variables
-12r-12=0
We move all terms containing r to the left, all other terms to the right
-12r=12
r=12/-12
r=-1

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