14-2(3x+1)=6(4+x)*

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Solution for 14-2(3x+1)=6(4+x)* equation: 



14-2(3x+1)=6(4+x)*

We move all terms to the left:

14-2(3x+1)-(6(4+x)*)=0

We add all the numbers together, and all the variables

-2(3x+1)-(6(x+4)*)+14=0

We multiply parentheses

-6x-(6(x+4)*)-2+14=0



We calculate terms in parentheses: -(6(x+4)*), so:

6(x+4)*

We multiply parentheses

6x+24

Back to the equation:

-(6x+24)



We add all the numbers together, and all the variables

-6x-(6x+24)+12=0

We get rid of parentheses

-6x-6x-24+12=0

We add all the numbers together, and all the variables

-12x-12=0

We move all terms containing x to the left, all other terms to the right

-12x=12

x=12/-12

x=-1

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