14-3(5t-12)=1+(20t+1)

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Solution for 14-3(5t-12)=1+(20t+1) equation:



14-3(5t-12)=1+(20t+1)
We move all terms to the left:
14-3(5t-12)-(1+(20t+1))=0
We multiply parentheses
-15t-(1+(20t+1))+36+14=0
We calculate terms in parentheses: -(1+(20t+1)), so:
1+(20t+1)
determiningTheFunctionDomain (20t+1)+1
We get rid of parentheses
20t+1+1
We add all the numbers together, and all the variables
20t+2
Back to the equation:
-(20t+2)
We add all the numbers together, and all the variables
-15t-(20t+2)+50=0
We get rid of parentheses
-15t-20t-2+50=0
We add all the numbers together, and all the variables
-35t+48=0
We move all terms containing t to the left, all other terms to the right
-35t=-48
t=-48/-35
t=1+13/35

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