14-3(5t-122)=1-(20t+1)

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Solution for 14-3(5t-122)=1-(20t+1) equation: 



14-3(5t-122)=1-(20t+1)

We move all terms to the left:

14-3(5t-122)-(1-(20t+1))=0

We multiply parentheses

-15t-(1-(20t+1))+366+14=0



We calculate terms in parentheses: -(1-(20t+1)), so:

1-(20t+1)

determiningTheFunctionDomain
-(20t+1)+1

We get rid of parentheses

-20t-1+1

We add all the numbers together, and all the variables

-20t

Back to the equation:

-(-20t)



We add all the numbers together, and all the variables

-15t-(-20t)+380=0

We get rid of parentheses

-15t+20t+380=0

We add all the numbers together, and all the variables

5t+380=0

We move all terms containing t to the left, all other terms to the right

5t=-380

t=-380/5

t=-76

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