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14-3(5x-12)=1-(20x-11)
We move all terms to the left:
14-3(5x-12)-(1-(20x-11))=0
We multiply parentheses
-15x-(1-(20x-11))+36+14=0
We calculate terms in parentheses: -(1-(20x-11)), so:We add all the numbers together, and all the variables
1-(20x-11)
determiningTheFunctionDomain -(20x-11)+1
We get rid of parentheses
-20x+11+1
We add all the numbers together, and all the variables
-20x+12
Back to the equation:
-(-20x+12)
-15x-(-20x+12)+50=0
We get rid of parentheses
-15x+20x-12+50=0
We add all the numbers together, and all the variables
5x+38=0
We move all terms containing x to the left, all other terms to the right
5x=-38
x=-38/5
x=-7+3/5
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