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14-3(x-3)=5+2(x+1)+x
We move all terms to the left:
14-3(x-3)-(5+2(x+1)+x)=0
We multiply parentheses
-3x-(5+2(x+1)+x)+9+14=0
We calculate terms in parentheses: -(5+2(x+1)+x), so:We add all the numbers together, and all the variables
5+2(x+1)+x
determiningTheFunctionDomain 2(x+1)+x+5
We add all the numbers together, and all the variables
x+2(x+1)+5
We multiply parentheses
x+2x+2+5
We add all the numbers together, and all the variables
3x+7
Back to the equation:
-(3x+7)
-3x-(3x+7)+23=0
We get rid of parentheses
-3x-3x-7+23=0
We add all the numbers together, and all the variables
-6x+16=0
We move all terms containing x to the left, all other terms to the right
-6x=-16
x=-16/-6
x=2+2/3
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