14-4(5t-12)=1-(20t+1)

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Solution for 14-4(5t-12)=1-(20t+1) equation:


Simplifying
14 + -4(5t + -12) = 1 + -1(20t + 1)

Reorder the terms:
14 + -4(-12 + 5t) = 1 + -1(20t + 1)
14 + (-12 * -4 + 5t * -4) = 1 + -1(20t + 1)
14 + (48 + -20t) = 1 + -1(20t + 1)

Combine like terms: 14 + 48 = 62
62 + -20t = 1 + -1(20t + 1)

Reorder the terms:
62 + -20t = 1 + -1(1 + 20t)
62 + -20t = 1 + (1 * -1 + 20t * -1)
62 + -20t = 1 + (-1 + -20t)

Combine like terms: 1 + -1 = 0
62 + -20t = 0 + -20t
62 + -20t = -20t

Add '20t' to each side of the equation.
62 + -20t + 20t = -20t + 20t

Combine like terms: -20t + 20t = 0
62 + 0 = -20t + 20t
62 = -20t + 20t

Combine like terms: -20t + 20t = 0
62 = 0

Solving
62 = 0

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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