14-4(x+3)=12(x+4)-28

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Solution for 14-4(x+3)=12(x+4)-28 equation: 



14-4(x+3)=12(x+4)-28

We move all terms to the left:

14-4(x+3)-(12(x+4)-28)=0

We multiply parentheses

-4x-(12(x+4)-28)-12+14=0



We calculate terms in parentheses: -(12(x+4)-28), so:

12(x+4)-28

We multiply parentheses

12x+48-28

We add all the numbers together, and all the variables

12x+20

Back to the equation:

-(12x+20)



We add all the numbers together, and all the variables

-4x-(12x+20)+2=0

We get rid of parentheses

-4x-12x-20+2=0

We add all the numbers together, and all the variables

-16x-18=0

We move all terms containing x to the left, all other terms to the right

-16x=18

x=18/-16

x=-1+1/8

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