14-5(x+1)=3(2-3x)+6x-5

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Solution for 14-5(x+1)=3(2-3x)+6x-5 equation: 



14-5(x+1)=3(2-3x)+6x-5

We move all terms to the left:

14-5(x+1)-(3(2-3x)+6x-5)=0

We add all the numbers together, and all the variables

-5(x+1)-(3(-3x+2)+6x-5)+14=0

We multiply parentheses

-5x-(3(-3x+2)+6x-5)-5+14=0



We calculate terms in parentheses: -(3(-3x+2)+6x-5), so:

3(-3x+2)+6x-5

We add all the numbers together, and all the variables

6x+3(-3x+2)-5

We multiply parentheses

6x-9x+6-5

We add all the numbers together, and all the variables

-3x+1

Back to the equation:

-(-3x+1)



We add all the numbers together, and all the variables

-5x-(-3x+1)+9=0

We get rid of parentheses

-5x+3x-1+9=0

We add all the numbers together, and all the variables

-2x+8=0

We move all terms containing x to the left, all other terms to the right

-2x=-8

x=-8/-2

x=+4

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