14-8(6-4x)=4(8x-7)-6

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Solution for 14-8(6-4x)=4(8x-7)-6 equation: 



14-8(6-4x)=4(8x-7)-6

We move all terms to the left:

14-8(6-4x)-(4(8x-7)-6)=0

We add all the numbers together, and all the variables

-8(-4x+6)-(4(8x-7)-6)+14=0

We multiply parentheses

32x-(4(8x-7)-6)-48+14=0



We calculate terms in parentheses: -(4(8x-7)-6), so:

4(8x-7)-6

We multiply parentheses

32x-28-6

We add all the numbers together, and all the variables

32x-34

Back to the equation:

-(32x-34)



We add all the numbers together, and all the variables

32x-(32x-34)-34=0

We get rid of parentheses

32x-32x+34-34=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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