14/12=(3x2)

Solution for 14/12=(3x2) equation:

14/12=(3x^2)

We move all terms to the left:

14/12-((3x^2))=0

determiningTheFunctionDomain
-3x^2+14/12=0

We multiply all the terms by the denominator


-3x^2*12+14=0

Wy multiply elements

-36x^2+14=0

a = -36; b = 0; c = +14;
Δ = b2-4ac
Δ = 02-4·(-36)·14
Δ = 2016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2016}=\sqrt{144*14}=\sqrt{144}*\sqrt{14}=12\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{14}}{2*-36}=\frac{0-12\sqrt{14}}{-72}
=-\frac{12\sqrt{14}}{-72}
=-\frac{\sqrt{14}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{14}}{2*-36}=\frac{0+12\sqrt{14}}{-72}
=\frac{12\sqrt{14}}{-72}
=\frac{\sqrt{14}}{-6}
$