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14/15v-5/6=8/9v-3
We move all terms to the left:
14/15v-5/6-(8/9v-3)=0
Domain of the equation: 15v!=0
v!=0/15
v!=0
v∈R
Domain of the equation: 9v-3)!=0We get rid of parentheses
v∈R
14/15v-8/9v+3-5/6=0
We calculate fractions
(-6075v^2)/4860v^2+4536v/4860v^2+(-4320v)/4860v^2+3=0
We multiply all the terms by the denominator
(-6075v^2)+4536v+(-4320v)+3*4860v^2=0
Wy multiply elements
(-6075v^2)+14580v^2+4536v+(-4320v)=0
We get rid of parentheses
-6075v^2+14580v^2+4536v-4320v=0
We add all the numbers together, and all the variables
8505v^2+216v=0
a = 8505; b = 216; c = 0;
Δ = b2-4ac
Δ = 2162-4·8505·0
Δ = 46656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{46656}=216$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(216)-216}{2*8505}=\frac{-432}{17010} =-8/315 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(216)+216}{2*8505}=\frac{0}{17010} =0 $
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