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14/4x-6=14+3x
We move all terms to the left:
14/4x-6-(14+3x)=0
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
14/4x-(3x+14)-6=0
We get rid of parentheses
14/4x-3x-14-6=0
We multiply all the terms by the denominator
-3x*4x-14*4x-6*4x+14=0
Wy multiply elements
-12x^2-56x-24x+14=0
We add all the numbers together, and all the variables
-12x^2-80x+14=0
a = -12; b = -80; c = +14;
Δ = b2-4ac
Δ = -802-4·(-12)·14
Δ = 7072
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7072}=\sqrt{16*442}=\sqrt{16}*\sqrt{442}=4\sqrt{442}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-4\sqrt{442}}{2*-12}=\frac{80-4\sqrt{442}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+4\sqrt{442}}{2*-12}=\frac{80+4\sqrt{442}}{-24} $
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