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14/x-2=10x
We move all terms to the left:
14/x-2-(10x)=0
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
-10x+14/x-2=0
We multiply all the terms by the denominator
-10x*x-2*x+14=0
We add all the numbers together, and all the variables
-2x-10x*x+14=0
Wy multiply elements
-10x^2-2x+14=0
a = -10; b = -2; c = +14;
Δ = b2-4ac
Δ = -22-4·(-10)·14
Δ = 564
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{564}=\sqrt{4*141}=\sqrt{4}*\sqrt{141}=2\sqrt{141}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{141}}{2*-10}=\frac{2-2\sqrt{141}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{141}}{2*-10}=\frac{2+2\sqrt{141}}{-20} $
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