140=(x+4)(x+9)-(x+5)(x)

Solution for 140=(x+4)(x+9)-(x+5)(x) equation:

140=(x+4)(x+9)-(x+5)(x)

We move all terms to the left:

140-((x+4)(x+9)-(x+5)(x))=0

We multiply parentheses ..

-((+x^2+9x+4x+36)-(x+5)x)+140=0


We calculate terms in parentheses: -((+x^2+9x+4x+36)-(x+5)x), so:

(+x^2+9x+4x+36)-(x+5)x

We multiply parentheses

(+x^2+9x+4x+36)-x^2-5x

We get rid of parentheses

x^2-x^2+9x+4x-5x+36

We add all the numbers together, and all the variables

8x+36

Back to the equation:

-(8x+36)


We get rid of parentheses

-8x-36+140=0

We add all the numbers together, and all the variables

-8x+104=0

We move all terms containing x to the left, all other terms to the right

-8x=-104

x=-104/-8

x=+13