140=2(53/4w-11)+2w

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Solution for 140=2(53/4w-11)+2w equation: 



140=2(53/4w-11)+2w

We move all terms to the left:

140-(2(53/4w-11)+2w)=0



Domain of the equation: 4w-11)+2w)!=0

w∈R



We multiply all the terms by the denominator


-(2(53+140*4w-11)+2w)=0



We calculate terms in parentheses: -(2(53+140*4w-11)+2w), so:

2(53+140*4w-11)+2w

We add all the numbers together, and all the variables

2(140*4w+42)+2w

We add all the numbers together, and all the variables

2w+2(140*4w+42)

We multiply parentheses

2w+1120w+84

We add all the numbers together, and all the variables

1122w+84

Back to the equation:

-(1122w+84)



We get rid of parentheses

-1122w-84=0

We move all terms containing w to the left, all other terms to the right

-1122w=84

w=84/-1122

w=-14/187

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