140=51+4f+1

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Solution for 140=51+4f+1 equation: 



140=51+4f+1

We move all terms to the left:

140-(51+4f+1)=0

We add all the numbers together, and all the variables

-(4f+52)+140=0

We get rid of parentheses

-4f-52+140=0

We add all the numbers together, and all the variables

-4f+88=0

We move all terms containing f to the left, all other terms to the right

-4f=-88

f=-88/-4

f=+22

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