1412c-3+5=5+3(c-14)

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Solution for 1412c-3+5=5+3(c-14) equation: 



1412c-3+5=5+3(c-14)

We move all terms to the left:

1412c-3+5-(5+3(c-14))=0

We add all the numbers together, and all the variables

1412c-(5+3(c-14))+2=0



We calculate terms in parentheses: -(5+3(c-14)), so:

5+3(c-14)

determiningTheFunctionDomain
3(c-14)+5

We multiply parentheses

3c-42+5

We add all the numbers together, and all the variables

3c-37

Back to the equation:

-(3c-37)



We get rid of parentheses

1412c-3c+37+2=0

We add all the numbers together, and all the variables

1409c+39=0

We move all terms containing c to the left, all other terms to the right

1409c=-39

c=-39/1409

c=-39/1409

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