141=30x+3(4x+5)

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Solution for 141=30x+3(4x+5) equation: 



141=30x+3(4x+5)

We move all terms to the left:

141-(30x+3(4x+5))=0



We calculate terms in parentheses: -(30x+3(4x+5)), so:

30x+3(4x+5)

We multiply parentheses

30x+12x+15

We add all the numbers together, and all the variables

42x+15

Back to the equation:

-(42x+15)



We get rid of parentheses

-42x-15+141=0

We add all the numbers together, and all the variables

-42x+126=0

We move all terms containing x to the left, all other terms to the right

-42x=-126

x=-126/-42

x=+3

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