142(3p+1)=6(4+p)

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Solution for 142(3p+1)=6(4+p) equation: 



142(3p+1)=6(4+p)

We move all terms to the left:

142(3p+1)-(6(4+p))=0

We add all the numbers together, and all the variables

142(3p+1)-(6(p+4))=0

We multiply parentheses

426p-(6(p+4))+142=0



We calculate terms in parentheses: -(6(p+4)), so:

6(p+4)

We multiply parentheses

6p+24

Back to the equation:

-(6p+24)



We get rid of parentheses

426p-6p-24+142=0

We add all the numbers together, and all the variables

420p+118=0

We move all terms containing p to the left, all other terms to the right

420p=-118

p=-118/420

p=-59/210

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