143=2x(4x-1)

Solution for 143=2x(4x-1) equation:

143=2x(4x-1)

We move all terms to the left:

143-(2x(4x-1))=0


We calculate terms in parentheses: -(2x(4x-1)), so:

2x(4x-1)

We multiply parentheses

8x^2-2x

Back to the equation:

-(8x^2-2x)


We get rid of parentheses

-8x^2+2x+143=0

a = -8; b = 2; c = +143;
Δ = b2-4ac
Δ = 22-4·(-8)·143
Δ = 4580
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4580}=\sqrt{4*1145}=\sqrt{4}*\sqrt{1145}=2\sqrt{1145}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{1145}}{2*-8}=\frac{-2-2\sqrt{1145}}{-16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{1145}}{2*-8}=\frac{-2+2\sqrt{1145}}{-16}
$