144=(5x-3)(5x-3)

Solution for 144=(5x-3)(5x-3) equation:

144=(5x-3)(5x-3)

We move all terms to the left:

144-((5x-3)(5x-3))=0

We multiply parentheses ..

-((+25x^2-15x-15x+9))+144=0


We calculate terms in parentheses: -((+25x^2-15x-15x+9)), so:

(+25x^2-15x-15x+9)

We get rid of parentheses

25x^2-15x-15x+9

We add all the numbers together, and all the variables

25x^2-30x+9

Back to the equation:

-(25x^2-30x+9)


We get rid of parentheses

-25x^2+30x-9+144=0

We add all the numbers together, and all the variables

-25x^2+30x+135=0

a = -25; b = 30; c = +135;
Δ = b2-4ac
Δ = 302-4·(-25)·135
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-120}{2*-25}=\frac{-150}{-50}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+120}{2*-25}=\frac{90}{-50}
=-1+4/5
$