144=(x-2)(2x-1)

Solution for 144=(x-2)(2x-1) equation:

144=(x-2)(2x-1)

We move all terms to the left:

144-((x-2)(2x-1))=0

We multiply parentheses ..

-((+2x^2-1x-4x+2))+144=0


We calculate terms in parentheses: -((+2x^2-1x-4x+2)), so:

(+2x^2-1x-4x+2)

We get rid of parentheses

2x^2-1x-4x+2

We add all the numbers together, and all the variables

2x^2-5x+2

Back to the equation:

-(2x^2-5x+2)


We get rid of parentheses

-2x^2+5x-2+144=0

We add all the numbers together, and all the variables

-2x^2+5x+142=0

a = -2; b = 5; c = +142;
Δ = b2-4ac
Δ = 52-4·(-2)·142
Δ = 1161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1161}=\sqrt{9*129}=\sqrt{9}*\sqrt{129}=3\sqrt{129}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-3\sqrt{129}}{2*-2}=\frac{-5-3\sqrt{129}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+3\sqrt{129}}{2*-2}=\frac{-5+3\sqrt{129}}{-4}
$