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144=x(25-x)
We move all terms to the left:
144-(x(25-x))=0
We add all the numbers together, and all the variables
-(x(-1x+25))+144=0
We calculate terms in parentheses: -(x(-1x+25)), so:We get rid of parentheses
x(-1x+25)
We multiply parentheses
-1x^2+25x
Back to the equation:
-(-1x^2+25x)
1x^2-25x+144=0
We add all the numbers together, and all the variables
x^2-25x+144=0
a = 1; b = -25; c = +144;
Δ = b2-4ac
Δ = -252-4·1·144
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-7}{2*1}=\frac{18}{2} =9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+7}{2*1}=\frac{32}{2} =16 $
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