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144=x(2x+2)
We move all terms to the left:
144-(x(2x+2))=0
We calculate terms in parentheses: -(x(2x+2)), so:We get rid of parentheses
x(2x+2)
We multiply parentheses
2x^2+2x
Back to the equation:
-(2x^2+2x)
-2x^2-2x+144=0
a = -2; b = -2; c = +144;
Δ = b2-4ac
Δ = -22-4·(-2)·144
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-34}{2*-2}=\frac{-32}{-4} =+8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+34}{2*-2}=\frac{36}{-4} =-9 $
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